Math, asked by rimjim2895, 1 year ago

Find the values of m for which exactly one root of the equation x^2-2mx+m^2-1 lies in the interval (-2 , 4) then m belongs to

Answers

Answered by rajivnld2002p7qvsa
14
sol is attached. value of multiplication at -2 & 4 should be negative
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Answered by nabanitammohanty
2

Answer:

root of the equation - x^2-2mx+m^2-1

m lies in the interval (-2,4)

substitute the value of x

(-2)^2-2m(-2)+m^2-1

4+4m+m^2-1

4^2-2m(2)+ m^2-1

16-8m+m^2-1

(4+4m+m^2-1)(16-4m+m^2-1)

(m^2+8m+15)(m^2-4m+3)

(m-5)(m-3)(m+1)(m+3)

m€(-3,-5) U m€(3,5)

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