Question

Find the values of m for which the equation x^2-(5+m)x+4=0

Answer 1

Let's solve for m.

x2−(5+m)(x)+4=0

Step 1: Add -x^2 to both sides.

−mx+x2−5x+4+−x2=0+−x2

−mx−5x+4=−x2

Step 2: Add 5x to both sides.

−mx−5x+4+5x=−x2+5x

−mx+4=−x2+5x

Step 3: Add -4 to both sides.

−mx+4+−4=−x2+5x+−4

−mx=−x2+5x−4

Step 4: Divide both sides by -x.

−mx/−x=−x2+5x−4/−x

m=x2−5x+4/x

Answer:

m=x2−5x+4/x


thanks
mark it as brainliest