Question

find the values of m for which y=mx does not intersect the circle x2 + y2 +20x +20y + 20 = 0​

Answer 1

Answer:

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Step-by-step explanation:

x

2

+(mx+2)

2

=1

x

2

+m

2

x

2

+4mx+4=1

(1+m

2

)x

2

+4mx+3=0

Hence, for real and unequal roots

a



=0,D>0

1+m

2



=0,16m

2

−12(1+m

2

)>0

or,m

2

>3

m>

3

and m<−

3