Question

Find the values of m so that the equation (3m+1)x^2 + 2(m+1)x + m = 0 has real and equal roots.

Answer 1

Answer:

m = (-31 ±√129)÷26

Step-by-step explanation:

(3m+1)x^2 + 2(m+1)x + m = 0 , to have real and equal roots,

16(m+1)² = m(3m+1)

16m²+32m+16 = 3m²+m

13m²+31m+16=0

m = (-31 ±√129)÷26

Answer 2

Answer:

see attached pictures

hope it helps