Question

Find the values of n of (2/3)^10× {(3/2)^2} ^5 = (2/3)^2n – 2

Answer 1

2/3'10 ×3/2'10 =2/3'10×2/3('-10)=2/3'0=••2/3'2n-2

base are equal.. 2n-2=0, n=1

Answer 2

I hope this answer will help you