Math, asked by swaradhinge, 7 days ago

Find the values of other five trigonometric functions 1. cos x = -1/2, x lies in third quadrant. Q2 Prove that \cos ^{2} x + \cos ^{2} (x + \frac{\pi}{3} ) + \cos ^{2} (x - \frac{\pi}{3} ) = \frac{3}{2}cos 2 x+cos 2 (x+ 3 π ​ )+cos 2 (x− 3 π ​ )=​

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Answered by XxLUCYxX
1

\cos ^{2} x + \cos ^{2} (x + \frac{\pi}{3} ) + \cos ^{2} (x - \frac{\pi}{3} ) = \frac{3}{2}cos 2 x+cos 2 (x+ 3 π  )+cos 2 (x− 3 π  )=

You forgot the equation \cos ^{2} x + \cos ^{2} (x + \frac{\pi}{3} ) + \cos ^{2} (x - \frac{\pi}{3} ) = \frac{3}{2}cos 2 x+cos 2 (x+ 3 π )+cos 2 (x− 3 π )= to put in insert formula

Answered by singhkusum4400
1

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