Question

Find the values of other five trigonometric functions in cos x = $\sf{\frac{-1}{2}}$, x lies in third quadrant.

Answer 1

Answer:

$cos x = \sf{\frac{-1}{2}} \\ cos \: x \: = cos \: 240 \degree \\ x = 240 \degree \\ \\ sin \: 240 \degree = \: - \frac{ \sqrt{3} }{2} \\ \\ tan \: 240 \degree = \: \sqrt{3} \\ \\ cot \: 240 \degree = \: \frac{1}{ \sqrt{3} } \\ \\ sec \: 240 \degree = \: - 2 \\ \\ cosec \: 240 \degree = \: \frac{ - 2}{ \sqrt{3} }$