Math, asked by xdemonjokerx230, 4 months ago

Find the values of p(0) and p(1) in p(y) = y2 – y + 1​

Answers

Answered by Anonymous
3
  1. p(y) =y^²-y+1
  2. p(0) =0^²-0+1
  3. p(0) =0-0+1
  4. p(0) =1
  5. p(1) =1^²-1+1
  6. p(1) =1-1+1
  7. p(1) =2-1
  8. p(1) =1
Answered by sana00070
3

Answer:

ʀ ʀ ɴ s ʙʀᴀɪɴʟɪᴇsᴛ.... :)

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