Find the values of p(0) and p(1) in p(y) = y2 – y + 1
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- p(y) =y^²-y+1
- p(0) =0^²-0+1
- p(0) =0-0+1
- p(0) =1
- p(1) =1^²-1+1
- p(1) =1-1+1
- p(1) =2-1
- p(1) =1
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