Question

Find the values of p(0) and p(1) in p(y) = y2 – y + 1

with explanations
I will mark as brainlist
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Answer 1

Answer:

p(0)=y²-y+1

=0²-0+1

=1

p(1)=y²-y+1

=1²-1+1

=1-1+1

=1

Answer 2

Step-by-step explanation:

Find the values of p(0) and p(1) in p(y) = y2 – y + 1

with explanations

I will mark as brainlist