Question

find the values of p(0),p(1)for p(t)=(t-1)(t+2)​

Answer 1

Answer:

-2,0

Step-by-step explanation:

Let t=0

p(0) = (0-1) (0+2)

= (-1)(2)

= -2

P (1) = (1-1) (1+2)

= 0(3)

=0

Answer 2

Step-by-step explanation:

p(t) = (t-1) (t+2)

p(0) = (0-1)(0+2) = -2

p(1) = (1-1)(1+2) = 0