Question

find the values of p(1),p(-1),p(0),p(-2),where p(x) =3x³-4x²+5x+7​

Answer 1

Answer:

Given P(x) = 3x³ - 4x² +5x +7

now,

P(1) = 3(1)³-4(1)²+5(1)+7 = 3-4+5+7 = 11

Similarly find the other values.

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Answer 2

Step-by-step explanation:

p (x) = 3x³-4x²+5x+7

p(1) =3(1)³-4(1)²+5(1)+7

= 3(1)-4(1)+5+7

= 3-4+5+7

=15-4

=11

p(-1)= 3(-1)³-4(-1)²+5(-1)+7

=3(-1)-4(1)+5(-1)+7

= -3-4-5+7

= -5