Question

find the values of p(1),p(-1),p(2),p(-2),p(0),in p(x) =x^2-7x-4​

Answer 1

Answer:

p(x)= x2-7x-4

putting value of x

p(1) = (1)2 - 7×1 -4

p(1)= 1-7-4

p(1)= -6-4

p(1)= -10

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Answer 2

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