Find the values of p and q for which the following system of linear equations has infinite number of solutions
2x + 3y = 7 and (p+q) x + ( 2p-q) y = 3 (p+q+1)
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Infinite solutions =a¹/a²=b¹/b²=c¹/c²
So
2/p+q=3/2p-q=7/3p+3q+3
So by first solving
2(2p-q)=3(p+q)
4p-2q=3p+3q
p=5q ¹
Also
7(2p-q)=3(3p+3q+3)
14p-7q=9p+9q+9
5p=16q+9
Value of P from ¹
25q=16q+9
9q=9
q=1
And p=5
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