Question

Find the values of p and q If they are zeros of the polynomial P of x=2x square plus p of x plus q

Answer 1

Answer:Given: f(x)=2x^2-7x+3

= 2x^2 - 6x -x +3

= 2x(x-3) -1(x-3)

=(2x-1)(x-3)

Hence, x=3 & x=1/2. 0r p=3 & q=1/2

Therefore, p^2 + q^2 = 3×3 + 1/2×1/2 = 9 + 1/4 = 37/4

Hope I was helpful.. :D

Answer 2

Given:

• The zeros of the polynomial x² - px + q are 3 and 2.

To find:

• The value of p and q.

Answer:

We know that the general form of a quadratic question is:

$\tt x^2\ -\ (sum\ of\ the\ zeros)x\ +\ (product\ of\ the\ zeros)$

Comparing the given equation with the general form, we get that the sum of the zeros is p and the product is q.

Let's take a sample equation.

ax² + bx + c

From this, the sum of the zeros is -b/a and the product is c/a.

Since 3 and 2 are the zeros,

Sum of the zeros ⇒ 3 + 2 = 5 = p

Product of the zeros ⇒ 3x2 = 6

Therefore, p = 5 and q = 6.