Find the values of p for which the
difference between the roots of the
equation x²+2x+8 =0 i 2.
Answers
Answered by
1
(x-2x)(x+4x)
Step-by-step explanation:
x2+4x-2x+8=0 x(x-2x)-(x+4)=(x-2x)(x+4x)
Answered by
1
Answer:
x2 + 2x +8 = 0
x2 + (4 - 2)x + 8 = 0
x2 + 4x - 2x + 8 = 0
2x (1 - 2) - 2x ( 1 - 4) = 0
(1-2) (2x- 2x)
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