Question

find the values of P for which the difference between the roots of the equation x^2+px+i=0 is 2​

Answer 1

Answer:

If difference of roots of the equation x^2 + px + 8 = 0 is 2 , then p is equal to:

Missing: y= ‎| Must include: y=

Answer 2

Answer:

-3

Step-by-step explanation:

x= 2

2² + p(2) + 2 = 0

4 + 2p + 2 = 0

2p + 6 = 0

p = -6/2

p = -3