Find the values of p for which the following
pair of linear equations have a unique solution :
(3p + 1)x - py + 7 = 0
2px + y - 3 = 0
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Given:
pair of linear equations :
(3p + 1)x - py + 7 = 0
2px + y - 3 = 0
they have unique solution
To Find:
The values of p for which the following
pair of linear equations has a unique solution.
Solution:
The condition for a unique solution is
⇒ a₁/a₂ ≠ b₁/b₂
so for eqn,
⇒ (3p + 1)x - py + 7 = 0
a₁ = ( 3p + 1) , b₁ = -p
⇒ 2px + y - 3 = 0
a₂ = 2p , b₂ = 1
∴ a₁/a₂ ≠ b₁/b₂ ⇒ ( 3p + 1) /2p ≠ -p/1
⇒ ( 3p + 1) ≠ -2p²
⇒ 2p² + 3p + 1 ≠ 0
⇒ 2p² + 2p + p + 1 ≠ 0
⇒ 2p ( p + 1 ) + 1 ( p + 1 ) ≠ 0
⇒ ( p + 1 ). ( 2p + 1 ) ≠ 0
⇒ ( p + 1 ) ≠ 0, ( 2p + 1 ) ≠ 0
⇒ p ≠ -1 , -1/2
Hence, the value of p will be any real number except -1 and -1/2.
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