Question

find the values of p for which the roots are real and equal P^2 x^2 - 2 (2p- 1) x+4 =​

Answer 1

Answer:

For roots to be real and equal, the condition is

b^2=4ac

Here b=-2(2p-1), a=p^2 and c=4

Putting these values in the above condition

{-2(2p-1)}^2=4p^2×4

(2p-1)^2=4p^2

4p^2-4p+1=4p^2

-4p=-1

p=1/4