Find the values of rational numbers a and b , if 2+ root 3/2- root 3= a+b root 3 find value of a and b
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Given:
(√3+√2)/(√3-√2) =a+b√6
Multiplying numerator and denominator of LHS with (√3+√2) we get―
=(√3+√2)(√3+√2)/[(√3-√2)(√3+√2)]
=[(√3+√2)^2]/(3-2) [using (a+b)(a-b)=a^2-b^2]
=(3+2+2√6)/1
=5+√6
On comparision with a+b√6, we see–
a=5 and b=2
[Answer]
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