find the values of the following expressions at a = -2 and b = 3
I) a3 + 3a2b + 3ab2 + b3
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Answer:
(-2)³+3(-2)²×2(3)+3(-2)(3)²+3³=31131
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a³ + 3a²b + 3ab² + b³
When a = -2 and b = 3
= (-2)³ + 3(-2)² (3) + 3 (-2) (3) + (3)³
= -8 + 9 x 4 - 18 + 27
= -8 + 36 - 18 + 27
= -26 + 63
= 37
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When a = -2 and b = 3
= (-2)³ + 3(-2)² (3) + 3 (-2) (3) + (3)³
= -8 + 9 x 4 - 18 + 27
= -8 + 36 - 18 + 27
= -26 + 63
= 37
Hope this helps you
Mark me as a brainlist please ❤️❤️
Bye ☺️
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