Math, asked by reddysasmita693, 8 months ago

Find the values of the following
(iv)
distributive property.
(i) 6753 x 98 + 2 x 6753
(ii) 75 x 813 + 187 x 75
(ili) 143 x 1001 - 143
(iv) 592 x 976 - 592 x 876​

Answers

Answered by angelinagac23
17

Answer:

675300

Step-by-step explanation:

a(b+c) =ab+ac

6753(98+2)=661794+13506

=675300

Answered by abarnaavijay
2

Answers:

i) 6753 x 98 + 2 x 6753

By distributive property,

A(B + C) = AB + AC

Here, A = 6753; B = 98; C = 2

By applying the formula we get

6753 x 98 + 2 x 6753 = 6753 (98 + 2)

                                    = 6753 x 100

                                    = 675300

Therefore the answer is 675300

ii) 75 x 813 + 187 x 75

By distributive property,

A(B + C) = AB + AC

Here, A = 75; B = 813; C = 87

By applying the formula we get,

75 x 813 + 187 x 75 = 75(813+187)

                               = 75 x 1000

                               = 75000

Therefore, the correct answer is 75000

iii) 143 x 1001 - 143

By distributive property,

A(B - C) = AB - AC

Here, A = 143; B = 1001; C = 0

By applying the formula we get,

143 x 1001 - 143 = 143(1001 - 0)

                          = 143 x 1001

                          = 143143

Therefore, the correct answer is 143143

iv) 592 x 976 - 592 x 876​

By distributive property,

A(B - C) = AB - AC

Here, A = 592; B = 976; C = 876

By applying the formula we get,

592 x 976 - 592 x 876 = 592(976-876)

                                     = 592 x 100

                                     = 59200

Therefore, the correct answer is 59200

#SPJ2

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