find the values of the following polynomials at a = -2 and b=3.
a. a2+2ab+b2.
b. a3- 3a2b + 3ab2- b3
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Answer:
Given polynomial is a 3−3a²b+3ab²−b³
Substituting the given values, we
get(−2)³ +3(−2)²(3)+3(−2)(3)² −(3)³
=−8+36−54−27
=−125
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