Math, asked by ramafhanider, 3 days ago

find the values of the following,v)log a√a​

Answers

Answered by llBAADSHAH2ll
0

We know the Logarithmic rules :

1 ) log a ( base a ) = 1

2 ) log ( a^m ) ( base a^n ) = m/n

3 ) log a^n = n log a

4 ) log 1 any base = 0

and

a^-n = 1/aⁿ

i ) log 5( base 25 )

= log 5¹ ( base 5² )

= 1/2

ii ) log 3 ( base 81 )

= log 3¹ ( base 3⁴ )

= 1/4

iii ) log ( 1/16 ) ( base 2 )

= log ( 1/2⁴ )( base 2 )

= log 2^-4 ( base 2 )

= -4 [ log 2 ( base 2 ) ]

= -4

iv ) log 1 ( base 7 )

= 0

v ) log √x ( base x )

= log x½ ( base x )

= 1/2 [ log x ( base x )]

= 1/2

vi ) log 512 ( base 2 )

= log 2^9 ( base 2 )

= 9 [ log 2 ( base 2 )]

= 9

vii ) log ( 0.01 )( base 10 )

= log ( 1/10 )² ( base 10 )

= log ( 10 )^-2 ( base 10 )

= -2 [ log 10 ( base 10 ) ]

= -2

viii ) log ( 8/27 ) ( base 2/3 )

= log ( 2/3 )³ ( base 2/3 )

= 3[ log (2/3 ) ( base 2/3 )]

= 3

I hope this helps you.

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Answered by vaibhavdantkale65
0

Answer:

(i) log

3

(3

−4

)=−4log

3

3=−4

(ii) log

7

7

3

=3log

7

7=3

(iii) log

6

6

5

=5log

6

6=5

(iv) log

1/2

8=log

2

−1

2

3

=

−1

3

log

2

2=−3

(v) log

10

10

−4

=−4log

10

10=−4

(vi) log

3

9

3

=log

3

(

3

)

3

=5log

3

3

=5

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