Find the values of the letters in following: 2 × 1 = 2 Marks 2 A B + A B 1 B 1 8
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A+8=3, then A has to be 5 because unit digit of the sum has to be 3.
There is a carry-over of 1.
So, 4+9+1=14
A=5,B=4 and C=1
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