Find the values of the other five trigonometric functions in each of the following:
(i) cot x = 12/5, x in quadrant III
(ii) cos x = -1/2, x in quadrant II
(iii) tan x = 3/4, x in quadrant III
(iv) sin x = 3/5, x in quadrant I
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Given that cos(t) = -3/5
a) sin(t)
Then sin2(t) + cos2(t) = 1
Substitute cos(t) value
sin2(t)+ ( -3/5)2= 1
sin2(t) = 1- 9/25
sin(t) = √ 16/25
Therefore sin(t) = 4/5
b) tan(t)
tan(t) = sin(t)/cos(t)
(4/5)/(-3/5) = - 4/3
Therefore tan(t) = - 4/3
Therefore sin(t) = 4/5 and tan(t) = -4/3.
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