Question

Find the values of the other five trigonometric functions in each of the following:

(i) cot x = 12/5, x in quadrant III

(ii) cos x = -1/2, x in quadrant II

(iii) tan x = 3/4, x in quadrant III

(iv) sin x = 3/5, x in quadrant I



Ye thode zyada nhi ho gye
xD...

Mai kuch nahi faltu ki tension le raha hu

what about you ?​

Answer 1

Answer:

Given cotx=43

tanx=cotx1=(43)1=34

1+tan2x=sec2x

⇒1+(34)2=sec2x

⇒1+916=sec2x

⇒925=sec2x

⇒secx=±35

Since x lies in the 3rd quadrant, the value of secx will be negative.

∴secx=−35

cosx=secx1=(−35)1=−5