Question

Find the values of the trigonometric ratios of angles ø and B in tje triangle shown below

Answer 1

Answer:

plz attach the triangle pic

Answer 2

Given :- Find the values of the trigonometric ratios of angles ø and β in the triangle shown below ?

Solution :-

First the given triangle must be an right angle ∆ .

so,

→ Hypotenuse = √(5)² + (4)² = √(25 + 16) = √41 .

now, we know that, 6 trigonometric ratios are :-

• sin θ = Perpendicular/Hypotenuse
• cos θ = Base/Hypotenuse
• tan θ = Perpendicular/Base
• cosec θ = Hypotenuse/Perpendicular
• sec θ = Hypotenuse/Base
• cot θ = Base/Perpendicular .

Trigonometric ratios of angle ø :-

→ sin ø = P/H = 4/√41

→ cos ø = B/H = 5/√41

→ tan ø = P/B = 4/5

→ cosec ø = H/P = √41/4

→ sec ø = H/B = √41/5

→ cot ø = B/P = 5/4

Trigonometric ratios of angle β :-

→ sin β = P/H = 5/√41

→ cos β = B/H = 4/√41

→ tan β = P/B = 5/4

→ cosec β = H/P = √41/5

→ sec β = H/B = √41/4

→ cot β = B/P = 4/5

Learn more :-

It sino + tano = m

tano - sino an

Then express the

values of m²-n² in terms

of M and N

https://brainly.in/question/13926306

tanA/(1-cotA) + cotA/(1-tanA)

https://brainly.in/question/16775946