Question

find the values of unknown in the following figures:​

Answer 1

In ∆ BCD,

BC = CD

=> angle DBC = angle BDC

50° = x

angle B + angle C + angle D = 180°

Angle C = 180° - 100°

z = 80°

Similarly, In ∆ABD

AB = Ad

=> angle ABD = angle ADB

Angle A + Agle B + Angle D = 180°

Angle A + 2(y) = 180°

2y = 180 - 100 = 80°

y = 40°

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Answer 2

step 1: The opponent angle of line BD are same so the corner connect with X is 50

step2: Since the some of all Angles of a triangle is 180

y+ 50 + 100=180

y= 30

similarly the step 1

X=30

similarly step 2

z= 100