Question

Find the values of x and y
5x+4y-4=0
x-20=12y

Answer 1

Given equations

$5x+4y-4=0\\5x+4y=4--(1)$

$\\x-20=12y\\x-12y=20--(2)$

Multiplying the first equation by 3, we get

$15x+12y=12$

Now solving,

$15x+12y=12\\\underline{x-12y=20}\\\underline{\underline{16x=32}}$

$x = \dfrac{32}{16}$

$\implies x=2$

Substituting the value of x in the second equation, we get,

$\implies 2-12y=20\\\implies -12y=20-2\\\implies -12y=18$

$\implies y = \dfrac{-18}{12} = \dfrac{-3}{2}$

$\boxed{\boxed{\bold{Therefore, \ the \ values \ of \ x \ and \ y \ are \ 2 \ and \ \frac{-3}{2} }}}}}}}}$

                                                       

Answer 2

Given:-

➜5x+4y=4-(1)

➜x-12y=20-(2)

$\rule{200}{1}$

To Find:-

✪The Values of x and y?

$\rule{200}{1}$

AnsWer:-

☞x=-4

☞y=12/7

$\rule{200}{1}$

★Multiply (2) with 5★

↝5x-60y=100-(3)

♦Subtract (3) and (1)♦

•5x+4y=4

•5x-60y=100

➜-56y=-96

➜y=$\frac{\cancel{-96}}{\cancel{-56}}$

☞y=$\frac{12}{7}$ or 1.71[Approx]-(4)

•Put (4) in (1)•

↝5x+4×$\frac{12}{7}$=4

↝5x+4×12=4×7

↝5x+48=28

↝5x=28-48

↝x=$\frac{\cancel{-20}}{\cancel{5}}$

↝x=-4

$\rule{200}{2}$