Question

find the values of x and y, if 4x+i(3x-y)=3-i6​

Answer 1

Answer: $x=\dfrac{3}{4}, y=\dfrac{33}{6}$

Step-by-step explanation: (Assuming x and y are real numbers) Comparing the real parts from both sides we get

$4x=3\Longrightarrow x=\dfrac{3}{4}$

Doing the same with the imaginary parts

$3x-y=-6 \Longrightarrow y=3x+6 \Longrightarrow y=3\cdot\dfrac{3}{4}+6=\dfrac{9}{4}+6=\dfrac{33}{6}$