Question

find the values of x and y if the distance of the point (x, y) from (-3, 9) as well as from (3, 0) are 4​

Answer 1

Answer:

Step-by-step explanation:

$d = \sqrt{(x_{2}-x_{1})^2 + (y_{2} -y_{1})^2}$

(a ± b)² = a² ± 2ab + b²

(x - h)² + (y - k)² = r² Circle equation

~~~~~~~~~~

For (x, y) and ( - 3, 9)

d² = (x + 3)² + (y - 9)² = 4²

For (x, y) and (3, 0)

d² =  (x - 3)² + y² = 4²

A( - 3, 9) and B(3, 0)

AB = √[(- 3 - 3)² + 9²] = 9√2 > (4 + 4)

There is no such a point , which satisfy both circle equations (1) and (2) , because distance between centers of circles > 2×4