Question

Find the values of x and y in the following ​

Answer 1

Answer:

I'm writing according (x, y) for each

Step-by-step explanation:

1.(55,55)

2.(100,50)

3.(120,30)

4.(40,70)

5.(60,150)

6.(50,130)

Answer 2

Answer:

Step-by-step explanation:

(i)∠x=∠y  {∠s opposite to equal sides are equal}

now in Δ

70+X+Y=180 {∠ sum property of a triangle}

70+X+X=180  {X=Y}

70+2X=180

2X=180-70

2X=110

X=110/2

X=55

X=55 , Y=55  {X=Y}

(ii)∠y=50 {angles opposite to equal sides are equal}

in triangle

∠y+50+∠a=180 {∠ sum property of a triangle}

50+50+∠a=180

100+∠a=180

∠a=180-100

∠a=80

∠a+∠x=180

80+x=180

x=180-80

x=100

(iii)∠y=30 {VERTICALLY OPPOSITE ANGLES}

IN TRIANGLE

∠Y+∠X+∠B=180 {∠ sum property of a triangle}

30+X+30=180

60+X=180

X=180-60

X=120

(iv)110+∠c=180

∠=180-110

∠c=70

∠y=∠c=70 {angles opposite to equal sides are equal}

in triangle

70+70+x=180 {∠ sum property of a triangle}

140+x=180

x=180-140

x=40

(v)30+∠y=180

∠y=180-30

∠y=150

in triangle

30+x+90=180 {∠ sum property of a triangle}

120+x=180

x=180-120=60

(vi) 80=∠e {vertically opposite angles}

in triangle

angle x=angle f {angles opposite to equal sides are equal}

x+f+80=180 {∠ sum property of a triangle}

x+x+80=180

2x+80=180

2x=180-80

2x=100

x=50

x+80=y {exterior angle property}

50+80=y

130=y