Find the values of x and y so that an odd number of the form 5yxy2x is divisible by both 3 and 5. give answer in steps
Answers
Answer:
Step-by-step explanation:
Given : An odd number of the form 5yxy2x is divisible by both 3 and 5.
We know : From divisibility rule for " 5 " that number can be divisible by 5 if unit digit is 0 or 5 .
So,
x can 0 or 5 , But also given our number 5yxy2x is an odd number , So we neglect x = 0 as at x = 0 number will became an even number , So
x = 5 , So our number : 5y5y25 ,
We know from divisibility rule of 3 that if sum of all digits is divisible by 3 so that number also divisible by 3 . So
5 + y + 5 + y +2 + 5 = 17 + 2 y Should be divisible by 3
Here we can see at y = 2 , 5 and 8 we get 17 + 2 y divisible by 3 , So
x = 5 and y = 2 , 5 and 8 ( Ans )