Math, asked by surabhitripatthi397, 3 months ago

Find the values of x and y so that the value of 3y+30 is smallee than 9x+3​

Answers

Answered by huzaifkhan3
1

Answer:

the value of x= -1/3 & y= -10

Step-by-step explanation:

3y + 30 < 9x+3 ---------(1)

Let, 3y+30=0 & 9x+3=0

3y= -30 & 9x= -3

y= -10 & x= -1/3

put value of x and y in equation (1)

3(-10)+30< 9(-1/3)+3

-30+30< 3+3

0<9

from above we get,

3y+30 <9x+3

and the value of x= -1/3 & y= -10

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