Math, asked by nano101, 1 year ago

Find the values of x and y using properties of a circle.

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luckkyramyasist: plzz mark as the best plzzz

Anonymous: x = 100 y = 130

nano101: which property did you use for X?

Anonymous: i don't know the name

Anonymous: the angle subtended by the common chord on the center is 2 the angle subtended by any other point on the circle to that chord

luckkyramyasist: no it is not right

TPS: souvik, you are correct. answer it.

nano101: how is x=100?

TPS: ABO is isosceles with OA=OB. so angle ABO is also 50. so AOB = 80. x = 180-AOB = 180-80 = 100

Anonymous: ok i am

Answers

Answered by parthgoel

angle DAB + angle DCB = 180 (sum of opposite sides of a cyclic quadrilateral)
angleDCB +50 =180
angle DCB =130
.'. angle y= 130

'.' OA=OB (radius of circle)
angle OAB = angle OBA = 50 (angles opposite to equal sides are equal)
angle OAB + angle OBA = angle BOD (exterior angle property of triangle)
50 +50 =angle x
100 =angle x

parthgoel: please mark it as a best answer

Answered by Anonymous

x = 100°

since the angle subtended by the common chord on the center is twice the angle subtended by any other point on the circle to that chord.

ABO is isosceles since
OA=OB= RADIUS OF THE CIRCLE.

so angle ABO = 50 .

so AOB = 80. x = 180 - AOB = 180 - 80 = 100

and is cyclic quadrilateral the opposite angles are supplementary

so y = 180 - 50 = 130°

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