Math, asked by supromallick3, 8 months ago

Find the values of x belongs to (0,2π)for which 2sin2x-5sinx+2>0.

Answers

Answered by rupeshrastogi382

0

x={π6}. Explanation: Use the substitution method and then factor. Let u=sin x. so, u2=sin2x. 2u2−5u+2=0. Now you can ...

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