Question

Find the values of x for which the distance between the points
A (-3, 2) and B (X, 6) is 25 units.​

Answer 1

Answer:

remember numbers are different

Step-by-step explanation:

use this method.

Answer 2

No values of x  the distance between the points  A (-3, 2) and B (X, 6) is 25 units.​

Step-by-step explanation:

Given : The distance between the points  A (-3, 2) and B (X, 6) is 25 units.​

To find : The values of x ?

Solution :

The distance formula between two point is given by,

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Here, $(x_1,y_1)=A(-3,2)$ and $(x_2,y_2)=B(x,6)$

and d=25 unit.

Substitute the value,

$25=\sqrt{(x-(-3))^2+(6-2)^2}$

Taking square root both side,

$\pm 5=(x+3)^2+4^2$

$\pm 5=x^2+9+6x+16$

$\pm 5=x^2+6x+25$

Taking 5,

$x^2+6x+25=5$

$x^2+6x+20=0$

Here, $D=b^2-4ac=(6)^2-4(1)(20)=-44<0$

Roots are imaginary so reject.

Taking -5,

$x^2+6x+25=-5$

$x^2+6x+30=0$

Here, $D=b^2-4ac=(6)^2-4(1)(30)=-84<0$

Roots are imaginary so reject.

Therefore, No values of x  the distance between the points  A (-3, 2) and B (X, 6) is 25 units.​

#Learn more

Find the value of x for which the distance between the points a(-3,2) and (x,6) is 25 units

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