Question

Find the values of x for which the distance between the points P(x, 4)
and Q(9, 10) is 10 units.
[CBSE 20111
info haninta DIO
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Answer 1

Step-by-step explanation:

by section formula u can solve it

Answer 2

Step-by-step explanation:

PQ = 10 units

underoot(x2 - x1)^2+(y2-y1)^2 = 10

(x-9)^2 + (4-10)^2 = 100

x^2 + 81 - 18x + 36 = 100

x^2 -18x +17 = 0

x^2 - 17x - x + 17 = 0

x (x-17) -1(x-17) = 0

(x-1)(x-17) = 0

x = 1, 17

P (1,4) or P (17,4)