find the values of x for which the distance between the points P(x,y) and Q(9,10) is 10 units
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this question same Ncrt book
ankurarora765:
i know btt can u help m in solving this
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distance formula 10 = 10-2 sq and y+3sq and 100 =64 +ysq +9+6 digit change kr dana
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Answer:
⇒ (PQ)2 = (10 units)2 = 100 units2
⇒ (9 – x)2 + (10 – 4)2 = 100
⇒ 81 – x2 – 18x + 36 = 100
⇒ x2 – 18x + 17 = 0
⇒ (x – 1) (x – 17) = 0
⇒ x = 1 or x = 17
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