Find the values of x if the distance between A (2, 0) and B(-1 , x) is equal to
5 units.
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given , A(2,0) and B(-1,x) [A(X1,y1),,,,,B(X2,y2)]
and AB= 5 unit
we know that:
√(x2-x1)^2+(y2-y1)^2 = AB
(-1-2)^2+(x-0)^2 = 5^2
(-3)^2+(x)^2 = 25
9+x^2 = 25
x^2 = 25-9
x^2 = 16
x = √16
x= 4 answer
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