Question

Find the values of x so that -2/7, x , -7/2 are 3 consecutive terms of a gp

Answer 1

Answer:

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Answer 2

The value of x is 1.

Step-by-step explanation:

Given : $-\frac{2}{7},x,-\frac{7}{2}$  are 3 consecutive terms of a GP.

To find : The value of x ?

Solution :

$-\frac{2}{7},x,-\frac{7}{2}$  are 3 consecutive terms of a GP.

Then the ratio between two consecutive term is same.

i.e. $\frac{a_1}{a_2}=\frac{a_2}{a_3}$

Here, $a_1=-\frac{2}{7},\ a_2=x,\ a_3=-\frac{7}{2}$

Substitute the value,

$\frac{-\frac{2}{7}}{x}=\frac{x}{-\frac{7}{2}}$

$x^2=-\frac{2}{7}\times -\frac{7}{2}$

$x^2=1$

$x=1$

Therefore, the value of x is 1.

#Learn more

In a geometric progression the product of three consecutive terms is 27 and the sum of the product of two terms taken at a time is 57/2. Find the three terms.​

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