Math, asked by navatare2, 9 months ago

Find the values of(x+y) and (x+y)
if 3x+4y=11: 4x+ 3y

Answers

Answered by giriaishik123
0

Answer:

3x + 4y = 11

4x + 3y = 10

x - y = - 1

x = y - 1

3(y-1) + 4y = 11

3y - 3 + 4y = 11

7y = 14

y = 2

3x = 11 - 8 = 3

x = 1

x + y = 1 + 2 = 3

Answered by dhruv220605
2

Answer:

3x + 4y = 11

3x + 4y = 114x + 3y = 10

3x + 4y = 114x + 3y = 10x - y = - 1

3x + 4y = 114x + 3y = 10x - y = - 1x = y - 1

3x + 4y = 114x + 3y = 10x - y = - 1x = y - 13(y-1) + 4y = 11

3x + 4y = 114x + 3y = 10x - y = - 1x = y - 13(y-1) + 4y = 113y - 3 + 4y = 11

3x + 4y = 114x + 3y = 10x - y = - 1x = y - 13(y-1) + 4y = 113y - 3 + 4y = 117y = 14

3x + 4y = 114x + 3y = 10x - y = - 1x = y - 13(y-1) + 4y = 113y - 3 + 4y = 117y = 14y = 2

3x + 4y = 114x + 3y = 10x - y = - 1x = y - 13(y-1) + 4y = 113y - 3 + 4y = 117y = 14y = 23x = 11 - 8 = 3

3x + 4y = 114x + 3y = 10x - y = - 1x = y - 13(y-1) + 4y = 113y - 3 + 4y = 117y = 14y = 23x = 11 - 8 = 3x = 1

3x + 4y = 114x + 3y = 10x - y = - 1x = y - 13(y-1) + 4y = 113y - 3 + 4y = 117y = 14y = 23x = 11 - 8 = 3x = 1x + y = 1 + 2 = 3

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