Question

Find the values of x,y and z
​

Answer 1

➤ Answer :-

${\tt \longrightarrow \dfrac{4}{( - 9)} = \dfrac{44}{\sf x} = \dfrac{\sf y}{36} = \dfrac{( - 144)}{\sf z}}$

In this problem, we will solve step by step.......

Value of 'x' :-

${\tt \longrightarrow \dfrac{4}{( - 9)} = \dfrac{44}{\sf x}}$

${\sf \longrightarrow (x) = \tt \dfrac{44}{4} \times ( - 9)}$

${\tt \longrightarrow \cancel\dfrac{44}{4} \times ( - 9) = \boxed{\tt 11 \times ( - 9)}}$

${\tt \longrightarrow \orange{\boxed{\sf (x) \: \tt = ( - 99)}}}$

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Value of 'y' :-

${\tt \longrightarrow \dfrac{4}{( - 9)} = \dfrac{ \sf y}{36}}$

${\sf \longrightarrow (y) = \tt \dfrac{36}{( - 9)} \times 4}$

$\tt \longrightarrow \cancel \dfrac{36}{( - 9)} \times 4 = \boxed{\tt ( - 4) \times 4}$

${\tt \longrightarrow \orange {\boxed{\sf (y) \tt = ( - 16)}}}$

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Value of 'z' :-

${\tt \longrightarrow \dfrac{4}{( - 9)} = \dfrac{( - 144)}{\sf z}}$

${\sf \longrightarrow (z) \tt \: = \dfrac{( - 144)}{4} \times ( - 9)}$

${\tt \longrightarrow \cancel \dfrac{( - 144)}{4} \times ( - 9) = \boxed{\tt ( - 36) \times ( - 9)}}$

${\tt \longrightarrow \orange{\boxed{\sf (z) = \tt 324}}}$

Answer 2

$\\ \large\mathfrak {\underline \purple{ \: \: \: \: \: \: \: \: question \mapsto \: \: \: \: \: \: \: \: }}$

Find the values of x , y and z

$\large \bf \bigstar \frac{4}{ - 9} = \frac{44}{x} = \frac{y}{36} = \frac{ - 144}{z} \bigstar$

$\\ \large\mathfrak {\underline \purple{ \: \: \: \: \: \: \: \: solution \mapsto \: \: \: \: \: \: \: \: }}$

$\large\ast \bf finding \: the \: value \: of \: \blue x \\ \\ \large \tt\blue➦ \frac{4}{( - 9)} = \frac{44}{x} \\ \\ \large \tt\blue➦ 4x = 44 \times ( - 9) \\ \\ \large \tt\blue➦ x = \frac {\cancel{44} {}^{11} \times ( - 9)} {\cancel{4} } \\ \\ \large \tt\blue➦ x = 11 \times ( - 9) \\ \\ \large \tt\blue➦ x = - 99 \\ \\ \large\sf \therefore \red{ \: the \: value \: of \: x \: is \: - 99}$

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$\large \bf \: finding \: the \: value \: of \: \blue y \\ \\ \large \tt\blue➦ \frac{4}{( - 9)} = \frac{y}{36} \\ \\ \large \tt\blue➦ 4 \times 36 = y \times ( - 9) \\ \\ \large \tt\blue➦ 144 = y \times ( - 9) \\ \\ \large \tt\blue➦ y \times ( - 9) = 144 \\ \\ \large \tt\blue➦ y = \frac {\cancel{144} {}^{16} }{ \cancel{ - 9} } \\ \\ \large \tt\blue➦ y = - 16 \\ \\ \large \bf \therefore \: \red{the \: value \: of \: y \: is \: - 16}$

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$\large \bf \: finding \: the \: value \: of \: \blue z \\ \\\large \tt\blue➦ \frac{4}{( - 9)} = \frac{( - 144)}{z} \\ \\ \large \tt\blue➦ 4 z =( - 144) \times ( - 9) \\ \\ \large \tt\blue➦ z = \frac {\cancel{ - 144} {}^{36} \times ( - 9)}{ \cancel{4} } \\ \\ \large \tt\blue➦ z = (- 36 )\times ( - 9) \\ \\ \large \tt\blue➦ z = 324 \\ \\ \large \bf \therefore \red{the \: value \: of \: z \: is \: 324}$

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$\\ \large\mathfrak {\underline \purple{ \: \: \: \: \: \: \: \: note \mapsto \: \: \: \: \: \: \: \: }}$

• Here we have Cross Multiplied the equation .

• In cross multiplication, we multiple the numerator of the first fraction with the denominator of the second fraction and the numerator of the second fraction with the denominator of the first .

• The top number is the numerator .

For ex ➲ 2/4 ........here 2 is the numerator.

• The bottom number is the denominator.

For ex ➲ 2/4 .........here 4 is the denominator.