Question

Find the values of x,y and z in the following figures.
Please help!tmrw is my exam.if you help me fast May god bless you.
If I get time I will mark you as brainliest for best

Answer 1

1]

65° + 20° + x = 180° [ angles on a straight line ]
85° +x = 180°
x = 95°

65° + 47° + y = 180. [ Angle sum property of triangle ]
112 + y = 180
y = 78°

y = 20 + z. [ exterior angle property of triangle ]
78° = 20 +z
z = 42°

Answer 2

ii.
x=180-(65+20)=180-85=95°
y
Angle sum prpty of ∆
180°-(65+47)=180-112=68°

z
exeterior angle prpty.
z=y-20=68-20=48°

iii

x=y=z

And x+x+50°= 180° [linear pair]

→2x=180-50=130°
→x=130/2=65°

→z=65°
→y=65°

Hope it helps...
Regards,
Leukonov.