Question

Find the values of x,y and z that satisfy sin-1x +sin-1y+sin-1z=2pi

Answer 1

Since maximum value of sin angle is 1 i.e., thus if we choose sin⁻¹x=sin⁻¹y=sin⁻¹z=π/2 [∵, sin(π/2)=1] that will satisfy the given equation as follows:sin⁻¹x+sin⁻¹y+sin⁻¹z=π/2+π/2+π/2=3π/2∴, x=y=z=sinπ/2=1∴, x+y+z=1+1+1=3 Ans.