Math, asked by sonunavya2007, 6 months ago

find the values of x,y for which the lines AD and BC becomes parallel​

Attachments:

Answers

Answered by subrataayshi
17

Answer:

X = 50° and Y = 20°

Step-by-step explanation:

5y° = 2x°

X° = 5y/2°

And we know, 30°=(X-Y)°

or, (5y/2)° - y° = 30°

or,(5y - 2y)/2° = 30°

or,3y/2° = 30°

or,3y = 30°× 2 = 60°

or, Y = 60/3° = 20°

or, X° - 20° = 30°

or, X° = 50°

so, X = 50° and Y = 20°

Answered by cheralasandhya4
4

Answer:

Given AD||BC5y°=2x.........(1) [alternate angles]

<BAC=180-5y-30

<BAC=150-5y

(150-5y)+2x+(x-y)=180

150-5y+2x+x-y=180

3x-6y=30

x-2y=10

X=10+2y............(2)

5y=2x...........(1)

X=10+2y..............(2)

substitute (2) into (1)

5y=2x

5y=2(10+2y)

5y=20+4y

5y-4y=20

y=20°

X=10+2y

X=10+2(20)

X=10+40

X=50°

Similar questions