Question

find the values of x,y if the distance point(x,y) from (-3,0) as well as (3,0) are 4

Answer 1

Answer:

P(x, y),Q(−3, 0) & R(3,0) Squaring both sides ⇒ 16=x2+9+6x+y2 ⇒ x2+y2=16-9-6x ⇒ x2+y2=7-6x .(1) Squaring both sides ⇒ 16=x2+9-6x+y2 ⇒ x2+y2=16-9+6x ⇒ x2+y2=7+6x (2) Equating (1) and (2) ⇒ 7-6x=7+6x ⇒ 7-7=6x+6x ⇒ 0=12x ⇒ x=0 Substituting the value of x=0 in (2) ⇒ x2+y2=7+6x ⇒ 0+y2=7+6x0 ⇒ y2=7 ⇒ y=±√7Read more on Sarthaks.com - https://www.sarthaks.com/103002/find-the-values-of-x-y-if-the-distances-of-the-point-x-y-from-3-0-as-well-as-from-3-0-are-4