Question

find the values of x,y,z in the figure.
pls give the whole solution.....and a proper,correct answer​

Answer 1

Answer:

Step-by-step explanation:

In△BCE

⟹∠BEC+∠BCE+∠CBE=180    

⟹90   +30  

∘

+∠CBE=180  

∘

⟹∠CBE=60  

∘

 

y=60  

∘

 

In△APC:

⟹50  

∘

+30  

∘

+∠APC=180  

∘

 

⟹∠APC=100  

∘

 

∴x=180−∠APC

(∵sumofanglesonastraightline=180  

∘

)

⟹x=180  

∘

−100  

∘

=80  

∘

 

In△BOP:

z=x+y(exteriorangleofatriangle=sumoftwooppositeinteriorangles)

⟹z=80+60=140  

∘

 

∴x=80  

∘

,y=60  

∘

,z=140  

∘