Find the values of x³-3x²-8x+15 when x=3+i
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Given : x=3+i
To Find : values of x³- 3x²-8x+15
Solution:
x³- 3x²-8x+15
= x²(x - 3) - 8x + 15
x=3+i
=> x - 3 = i
x=3+i
=> x² = 9 + i² + 6i
=> x² = 9 - 1 + 6i
=> x² = 8 + 6i
= (8 + 6i)(i) - 8(3 + i) + 15
= 8i + 6i² - 24 - 8i + 15
= 8i - 6 - 24 - 8i + 15
= -30 + 15
= - 15
values of x³- 3x²-8x+15 = - 15 when x = 3 + i
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