Question

find the values of y for which the distance between the points p(2,-3) and Q(10,y) is 10 units

Answer 1

Sol:
Let,
 x₁ = 2,
 x₂ = 10,
 y₁ = y,
 y₂ = -3

∴We have,

PQ = 10 units
⇒PQ² = 100
⇒(x₂-x₁)² + (y₂-y₁)² = 100
⇒(10-2)² + (-3-y)² = 100
⇒64 + (-3-y)² = 100
⇒(-3-y)² = 36
⇒-3-y = +6 or -6
⇒ y = -9 or 3

∴ value of y =-9 or 3

Answer 2

it is sais that distance between p(2,-3) and Q(10,y) is 10 units
hope it helps